49x^2+287x+42=0

Solution for 49x^2+287x+42=0 equation:

49x^2+287x+42=0

a = 49; b = 287; c = +42;
Δ = b2-4ac
Δ = 2872-4·49·42
Δ = 74137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{74137}=\sqrt{49*1513}=\sqrt{49}*\sqrt{1513}=7\sqrt{1513}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(287)-7\sqrt{1513}}{2*49}=\frac{-287-7\sqrt{1513}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(287)+7\sqrt{1513}}{2*49}=\frac{-287+7\sqrt{1513}}{98}
$